b^2=3(b-3)

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Solution for b^2=3(b-3) equation:


Simplifying
b2 = 3(b + -3)

Reorder the terms:
b2 = 3(-3 + b)
b2 = (-3 * 3 + b * 3)
b2 = (-9 + 3b)

Solving
b2 = -9 + 3b

Solving for variable 'b'.

Reorder the terms:
9 + -3b + b2 = -9 + 3b + 9 + -3b

Reorder the terms:
9 + -3b + b2 = -9 + 9 + 3b + -3b

Combine like terms: -9 + 9 = 0
9 + -3b + b2 = 0 + 3b + -3b
9 + -3b + b2 = 3b + -3b

Combine like terms: 3b + -3b = 0
9 + -3b + b2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-9' to each side of the equation.
9 + -3b + -9 + b2 = 0 + -9

Reorder the terms:
9 + -9 + -3b + b2 = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -3b + b2 = 0 + -9
-3b + b2 = 0 + -9

Combine like terms: 0 + -9 = -9
-3b + b2 = -9

The b term is -3b.  Take half its coefficient (-1.5).
Square it (2.25) and add it to both sides.

Add '2.25' to each side of the equation.
-3b + 2.25 + b2 = -9 + 2.25

Reorder the terms:
2.25 + -3b + b2 = -9 + 2.25

Combine like terms: -9 + 2.25 = -6.75
2.25 + -3b + b2 = -6.75

Factor a perfect square on the left side:
(b + -1.5)(b + -1.5) = -6.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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